Originally Posted by
RedPanda
IIInsanEEE, wrong answer. The correct answer is clearly ty dfg.
Meh, at least "lel" is better than "k" so y'know. I guess we can still be friends.
Also mod wise it goes ABD > Aikido > Mushu > Pooosssiiblllly Boxshu.
For Kookoo ErthTk > Aikido > Mushu > Boxshu > Maybe Lenshu3 ng > ABD. This might not be 100% correct but I think it's pretty close.
Kookoo doesn't like ABD as much as the rest, I do find it too serious at times so it's nice to play mushu or boxshu every now and then.
This poll will close on Apr 29, 2015 at 06:44 PM ty dfg Give2Kookoo, goddamnitred, jmoran232545343, Kookoo11, PhoenixClanBank, RedPanda, topmostkek, Zelda
8 38.10
ty dfg is clearly winning because it's the best. def not all alts of mine and kookoo's. only Zelda isn't one of our alts, the rest are 'legit'
I'll give TC to whoever can separate each alt and pair them with their owner, so whether they're my alts or kookoo's.
When did I ever play boxshu?
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Originally Posted by
Ele
I vote yes. Well-written, well-thought-out application. He has a strong command of the English language and has a flawless infraction record. I think he's absolutely suitable to be a Phoenix member.
Yes.
My answer to his application is take the "Yes", turn it around so it says "sey", remove the s and the e, so you get only the y. After that, add a "n" before the y so it looks like "ny". Now if you calculate how much I give a fuck about this application, you will finally replace that number with a letter that looks near exact like it, then replace it with the y.
Last edited by Kookoo11; Mar 13, 2015 at 03:54 PM.
Reason: <24 hour edit/bump